Problems Involving All Directions Turning
Problems Involving All Directions Turning
Direction Question: This section of verbal reasoning revolves around the various directions. It consist of questions involving all sort of direction puzzle. Candidate is required to make a successive follow-up of directions and ascertain the final direction or the distance between two points. The test is meant to judge the candidate,s ability to trace and follow correctly and sense the directions correctly.
Directions: There are four basic directions North N, South S, East E, West W and four cardinal directions North East NE, North West NW, South East SE, South West SW to help the candidates know the directions. The figure shows all the directions
Problems Involving All Directions: These type of questions are solved by taking the right and left movement of a person is always with reference to the body moving in the scenario. It is not with respect to the person who is solving the questions.A diagram is drawn showing the movement of the object. On analysing the diagram the candidate reaches the desired result
Illustration: If you are facing north-east and move 10 m forward, turn left and move 7.5 m, then you are
A. North of your initial position B. South of your initial position C. East of your initial position D. 12 m from your initial position.
Answer: A
Solution: Clearly, the narrator starts from A, moves towards north-east a distance of 10 m and reaches B, turns left ( anti-clockwise ) and moves 7.5 m and reaches C.
Clearly, C lies to the north of A.
Also, ABC is right-angled at B. So by Pythagoras Theorem
So,
= 100 + 56.25 = 156.25.
Thus, the narrator is 12.5 m to the north of his initial position. Hence option A is correct.
Illustration: A person starts from a point A and travels 3 km eastwards to B and then turns left and travels thrice that distance to reach C. He again turns left and travels five times the distance he covered between A and B and reaches his destination D. The shortest distance between the starting point and the destination is
A. 12 km B. 15 km C. 16 km D. 18 km
Answer: B
Solution: The movements of the person are as shown in fig.
Clearly, AB = 3 km,
BC = 3AB = (3 3) km = 9 km,
CD = 5AB = (5 3) km = 15 km.
Draw AE CD.
Then, CE = AB = 3 km and AE = BC = 9 km.
DE = (CD - CE) = (15 - 3) km = 12 km.
In AED,
=
+
AD =
km
= Km
= km = 15 km.
Required distance = AD = 15 km
Hence the correct option is B
Preeti started for her office. She moved south for 1 km and turned left. She covered 400 m and turned left again. She moved 1 km and turned right. She moved for 510 m and reached her office. How much is the straight distance between her house and her office? | |||
| Right Option : C | |||
| View Explanation | |||
A watch shows time 4.30 p.m. If the minute hand point towards East, in which direction will the hour hand point? | |||
| Right Option : D | |||
| View Explanation | |||
Vinod is driving a car, he moves in north and covers a distance of 30 km and than turns left and covers a distance of 30 km, and than turns right and covers a distance of 30 km, and than again turns left and covers a distance of 50 km. What is the minimum distance covered by Vinod? | |||
| Right Option : A | |||
| View Explanation | |||
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